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+1 vote
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in Physics by (21.2k points)

Four particles A, B, C, D of mass \( \frac{m}{2}\) , m, 2m, 4m, have same momentum, respectively. The particle with maximum kinetic energy is : 

(1) D 

(2) C 

(3) A 

(4) B

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1 Answer

+1 vote
by (20.6k points)

Correct option is : (3) A

\( \text { Kinetic energy }=\frac{\mathrm{P}^2}{2 \mathrm{m}}\)

\(\mathrm{P} \Rightarrow \text { momentum (same for all) }\)

\(\mathrm{KE} \propto \frac{1}{\text { mass }}\)

particle A is of least mass, have maximum kinetic energy

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