Question

Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = _________. 

(Given a₀ = 0.529Å, E = energy of electron in ground state)

Answer 1

Correct answer is : 16

We know

\(\mathrm{r}=0.529 \frac{\mathrm{n}^{2}}{\mathrm{Z}} \Rightarrow 8.48=0.529 \frac{\mathrm{n}^{2}}{1}\)

\(\mathrm{n}^{2}=16 \Rightarrow \mathrm{n}=4\)

We know

\(\mathrm{E} \propto \frac{1}{\mathrm{n}^{2}}\)

\(\mathrm{E}_{\mathrm{n}^{\text {th }}}=\frac{\mathrm{E}}{16}\)

\(\mathrm{x}=16\)