If Mo is the mass of isotope 5^12 B, Mp and Mn are the masses of proton and neutron, then nuclear binding energy

Question

If \( M_{0}\) is the mass of isotope \({ }_{5}^{12} B,\ M_{p}\) and \(M_{n}\) are the masses of proton and neutron, then nuclear binding energy of isotope is :

(1) \(\left(5 \ M_{p}+7 M_{n}-M_{o}\right) C^{2}\)

(2) \(\left(\mathrm{M}_{\mathrm{o}}-5 \mathrm{M}_{\mathrm{p}}\right) \mathrm{C}^{2}\)

(3) \( \left(\mathrm{M}_{\mathrm{o}}-12 \mathrm{M}_{\mathrm{n}}\right) \mathrm{C}^{2}\)

(4) \(\left(M_{0}-5 M_{p}-7 M_{n}\right) C^{2}\)  

Answer 1

Correct option is : (1) \(\left(5 \ M_{p}+7 M_{n}-M_{o}\right) C^{2}\) 

B.E. \(=\Delta \mathrm{mC}^{2}\)

\(\left(5 \ M_{p}+7 M_{n}-M_{o}\right) C^{2}\)