Question

A body of mass 2 kg has an initial velocity of 3 m/s along OE and it is subjected to a force of 4 Newton’s in OF direction perpendicular to OE. The distance of the body from O after 4 seconds will be 

(a)12 m 

(b) 28 m 

(c) 20 m 

(d) 48 m

Answer 1

Correct option (c) 20 m

Explanation:

Body moves horizontally with constant initial velocity 3 m/s upto 4 seconds 

∴ x = ut = 4 x 3 =12 m 

and in perpendicular direction it moves under the effect of constant force with zero initial velocity upto 4 seconds.