The emf of cell Tl |Tl^+ (0.001M)| |Cu^2+ (0.01M)| Cu is 0.83 V at 298 K. It could be increased by

Question

The emf of cell \(Tl\left|\underset {(0.001M)}{Tl^+}\right|\left|\underset {(0.01M)}{Cu^{2+}}\right| Cu\) is 0.83 V at 298 K. It could be increased by

(1) increasing concentration of \(Tl^+\) ions 

(2) increasing concentration of both \(Tl^+\) and \(Cu^{2+}\) ions 

(3) decreasing concentration of both \(Tl^+\) and \(Cu^{2+}\) ions 

(4) increasing concentration of \(Cu^{2+}\) ions

Answer 1

Correct option is (4) increasing concentration of \(Cu^{2+}\) ions

\(\begin{equation} \frac{ \begin{array}[b]{r} (Tl\,\rightarrow \,Tl^+ +e^-)\times 2\\ Ca^{2+}+2e^- \rightarrow \,Cu \end{array} }{ 2Tl+Cl^{2+} \rightarrow \,2Tl^+ + Cu } \end{equation}\)

\(E_{cell} = E ^0 _ {cell} - \frac {0.0591}{2}log \frac {[Tl^+]^2}{[Cu^{2+}]}\)