Question

A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is ______ (Integer Answer) (Given : Molar mass in g \(mol^{-1}\) Ethyl alcohol : 46, water : 18)

Answer 1

Correct answer is : 22

Mass of ethyl alcohol = 1 mole x MM

\(\Rightarrow \) 46g

Mass of water \(\Rightarrow 9\,mole \times MM\)

\(\Rightarrow 162\,g\)

% by mass of ethyl alcohol \(=\frac {46}{162+46} \times 100\)

⇒ 22% (approx.)