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A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. The magnitude of the angular momentum of the particle about the point of projection when the particle is at its maximum height is (where g = acceleration due to gravity)

(a) Zero

(b) mv3/(4√2g)

(c) mv3/)2g

(d) mv2/2g  

1 Answer

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Best answer

Correct option (b) mv3/(4√2g)

Explanation:

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