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\(_{82}^{290} X \xrightarrow{\alpha} Y \xrightarrow {e^+} Z \xrightarrow {\beta^-}P\xrightarrow {e^-}Q\)

In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are : 

(1) 280, 81 

(2) 286, 80 

(3) 288, 82 

(4) 286, 81

1 Answer

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Best answer

Correct option is : (4) 286, 81 

\({}_{82}^{290}X \xrightarrow{\alpha}{}_{80}^{286}Y\xrightarrow{e^+}{}_{79}^{286}Z \xrightarrow{\beta^-}{}_{80}^{286}P\xrightarrow{e^-}{}_{81}^{286}Q\)

\(A \rightarrow286\)

\(Z = 81\)

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