Question

Given below are two statements: 

Statement I : The boiling point of hydrides of Group 16 elements follow the order \( H_2O > H_2Te > H_2Se > H_2S. \)

Statement II: On the basis of molecular mass, \(H_2O\) is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in \(H_2O\), it has higher boiling point. 

In the light of the above statements, choose the correct answer from the options given below: 

(1) Both Statement I and Statement II are true 

(2) Both Statement I and Statement II are false 

(3) Statement I is true but Statement II is false 

(4) Statement I is false but Statement II is true

Answer 1

Correct option is : (1) Both Statement I and Statement II are true 

Statement I is correct, because boiling point of hydrides of group 16 follows the order \( H_2O > H_2Te > H_2Se > H_2S. \)

Statement II due to intermolecular H-bonding \(H_2O\) shows higher boiling point than respective hydrides of group 16. 

(Both Statement are true) 

Order from \(H_2Te\) to \(H_2S\) is due to decreasing molar mass.