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The highest number of helium atoms is in 

(1) 4 mol of helium 

(2) 4 u of helium 

(3) 4 g of helium 

(4) 2.271098 L of helium at STP

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Correct option is : (1) 4 mol of helium 

(1) 4 mol of He = 4 \(N_A\) He atoms

(2) 4 u of He = \(\frac{4\ u}{4\ u}\) = 1 He atom 

(3) 4 g of Helium = \(\frac{4\ g}{4\ g}\) mole = 1 mole = \(N_A\) He atom

(4) 2.2710982 of He at STP = \(\frac{2.271}{22.710982}\text{mole}\) 

\( = 0.1\ mole\) 

\(= 0.1\ N_A \ He\ \text{atom}\) 

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