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Match List I with List II.

List I (Conversion) List II (Number of Faraday required)
A. 1 mol of \(H_2O\) to \(O_2\) I. 3F
B. 1 mol of \(MnO^-_4\) to \(Mn^{2+}\) II. 2F
C. 1.5 mol of Ca from molten \(CaCl_2\) III. 1F
D. 1 mol of FeO to \(Fe_2O_3\) IV. 5F

Choose the correct answer from the options given below: 

(1) A-II, B-IV, C-I, D-III 

(2) A-III, B-IV, C-I, D-II 

(3) A-II, B-III, C-I, D-IV 

(4) A-III, B-IV, C-II, D-I

1 Answer

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Best answer

Correct option is (1) A-II, B-IV, C-I, D-III 

\(4OH^- \rightarrow 2H_2 O + O_2 + 4e ^-\)

for 2 mole of \(H_2O\) = 4F charge is required

for 1 mole of \(H_2O\) \(=\frac {4F}{2} = 2F\) required

\(\overset{+7}{MN} O^-_4 \rightarrow \overset {+2}{Mn^{2+}}\)

for 1 mole \(MnO ^- _4\) 5F charge is required

\(Ca^{2+} \xrightarrow {+2e ^-} Ca\)

For 1 mole \(Ca^{2+}\) ion required = 2F

1.5 mole \(Ca^{2+}\) ion required \(=\frac {2}{1} \times 1.5 = 3F\)

\(\overset {+2}{Fe}O \rightarrow \overset {+3}{Fe}_2O_3\)

for 1 mole FeO, 1F charge is required.

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