Correct option is (1) A-II, B-IV, C-I, D-III
\(4OH^- \rightarrow 2H_2 O + O_2 + 4e ^-\)
for 2 mole of \(H_2O\) = 4F charge is required
for 1 mole of \(H_2O\) \(=\frac {4F}{2} = 2F\) required
\(\overset{+7}{MN} O^-_4 \rightarrow \overset {+2}{Mn^{2+}}\)
for 1 mole \(MnO ^- _4\) 5F charge is required
\(Ca^{2+} \xrightarrow {+2e ^-} Ca\)
For 1 mole \(Ca^{2+}\) ion required = 2F
1.5 mole \(Ca^{2+}\) ion required \(=\frac {2}{1} \times 1.5 = 3F\)
\(\overset {+2}{Fe}O \rightarrow \overset {+3}{Fe}_2O_3\)
for 1 mole FeO, 1F charge is required.