Question

The Henry’s law constant \((K_H)\) values of three gases (A, B, C) in water are 145, \(2\times 10 ^{-5}\) and 35 kbar, respectively. The solubility of these gases in water follow the order: 

(1) B > A > C 

(2) B > C > A 

(3) A > C > B 

(4) A > B > C

Answer 1

Correct option is (2) B > C > A 

Value of Henry’s law constant \(\propto \frac {1}{\text {Solubility of gas}}\)

Higher the value of \(K_H\) at a given pressure, lower is the solubility of the gas in the liquid.

\(K_H\) value of gases (given) : A > C > B 

\(\therefore\) Order of solubility of gases in water : B > C > A