Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
181 views
in Logarithm by (15 points)
(log_a(bc))/(1 + log_a(bc)) + (log_b(ca))/(1 + log_b(ca)) + (log_c(ab))/(1 + log_c(ab)) = 2

Please log in or register to answer this question.

1 Answer

0 votes
by (1.5k points)

loga(bc)/(1 + loga(bc)) + logb(ca)/(1 + loga(ca)) + logc(ab)/(1 + logc(ab))

First Term

 logabc/(1 + loga(bc)) = logabc/(logaa + loga(bc)) = logabc/( loga(abc)) = log(bc)/log (abc)

Second Term

logbca/(1 + logb(ca)) = logbca /(logbb + loga(ca)) = logbca /( logb(abc)) = log(ca)/log (abc)

Third Term

logcab/(1 + logc(ab)) = logcab /(logcc + logc(ab)) = logcab /( logc(abc)) = log(ab)/log (abc)

Adding all three terms

log(bc)/log (abc) + log(ca)/log (abc) + log(ab)/log (abc) = log (bccaab)/ log (abc)

=log(abc)2/log(abc) = 2 log(abc)/log(abc)

=2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...