loga(bc)/(1 + loga(bc)) + logb(ca)/(1 + loga(ca)) + logc(ab)/(1 + logc(ab))
First Term
logabc/(1 + loga(bc)) = logabc/(logaa + loga(bc)) = logabc/( loga(abc)) = log(bc)/log (abc)
Second Term
logbca/(1 + logb(ca)) = logbca /(logbb + loga(ca)) = logbca /( logb(abc)) = log(ca)/log (abc)
Third Term
logcab/(1 + logc(ab)) = logcab /(logcc + logc(ab)) = logcab /( logc(abc)) = log(ab)/log (abc)
Adding all three terms
log(bc)/log (abc) + log(ca)/log (abc) + log(ab)/log (abc) = log (bccaab)/ log (abc)
=log(abc)2/log(abc) = 2 log(abc)/log(abc)
=2