Question

A charge of 10 C each is given to two spherical conductors A and B. The volumes of A and B are in ratio of 1:3. When A and B are connected by a conducting wire, show that it is impossible for the charge to flow from B to A.

Answer 1

Potential on the surface of spherical conductor \( = V = \frac{Q}{C} = \frac{Q}{4\pi \varepsilon _0R}\) 

The greater volume of sphere B corresponds to a greater radius \(R_B. R_A < R_B .\) 

So for the same charge given to the two spherical conductors, the conductor with a smaller radius, that is, B is at the lower potential. 

\(V_A > V_B\) 

The charge always flows from a body at a higher potential to a body at a lower potential. 

Hence, it is impossible for the charge to flow from B to A as \(V_B < V_A.\)