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If f and g are continuously differentiable show that ∇f × ∇g is a solenoidal.

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A vector F is solenoidal if ∇ ⋅ vector F = 0. To show that ∇f × ∇g is solenoidal. First we show that ∇f × ∇g can be expressed as a curl of a vector. We can show this using the identity.

∇ × (f∇g) = ∇f × ∇g + f∇ + ∇g

= ∇f × ∇g (∵ curl glad is zero)

Operating divergence on this and using the identity

∇ × ∇(f ∇ g) = 0  (∵ div curl of any vector is zero)

This gives ∇.(∇f × ∇g) = 0

Hence, ∇f × ∇g is solenoidal and hence proved.

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