Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
691 views
in Physics by (46.6k points)
closed by

A small piece of paper is stuck on the surface of the glass sphere of radius 10 cm and refractive index 1.5. The paper is viewed from diametrically opposite side. 

a. Represent the image formation using a ray diagram. 

b. Determine the image position.

1 Answer

+1 vote
by (49.9k points)
selected by
 
Best answer

a. 

the image formation using a ray diagram.

b. Using,

\(\frac{n_2}{v} - \frac{n_1}{u} = \frac{n2 - n1}{R}\) 

Here,

u = -20 cm, R = -10 cm, n1 = 1.5, n2 = 1

Upon substituting and calculating 

1/v = -1/40

v = -40 cm 

Image is formed 20 cm behind the glass ball.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...