Question

How many Faradays of charge are required to reduce \( 1 mol \) of \( Cr _{2} O _{7}^{2-} \) to \( Cr ^{+3} \) ? [NCERT Pg. 88](1) \( 6 F \)(2) \( 3 F \)(3) \( 2 F \)(4) \( 1 F \)

How many Faradays of charge are required to reduce

Answer 1

Correct option is (1) 6F

1 mol \(Cr_2O_7^{2-}\) requires 6 moles electron = 6F charge

∴ Number of Faraday's required = 6.