Question

A system absorbs \( 200 J \) of heat and does work. The change in internal energy \( (\Delta U) \) for the process is \( 460 I \). The work done by the system is \( \qquad \) (A) \( -660 J \) (b) \( 660 J \) 0.2. Answer the followingt

Answer 1

The correct answer is (a) -660 J​​​

To solve this problem, we can use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) minus the work done by the system (W). Mathematically, it's expressed as:

[ΔU= Q - W ]

Given that ( ΔU = 460 J ) and ( Q = 200 J ) we can rearrange the equation to solve for ( W ):

[ W = Q - ΔU]

[ W = 200 J - 460 J]

[ W = -260 J]

So, the work done by the system is ( -260 J).

The correct answer is (A) (– 660 J).