Question

At room temperature, disproportionation of an aqueous solution of in situ generated nitrous acid \((HNO_2)\) gives the species

(A) \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}\) and \(\mathrm{NO}\)

(B) \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}\) and \(\mathrm{NO}_2\)

(C) \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}^{-}\) and \(\mathrm{NO}_2\)

(D) \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}\) and \(\mathrm{N}_2 \mathrm{O}\)

Answer 1

Correct option is (A) \(\mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-}\) and \(\mathrm{NO}\)

\( \underset{+3}{3 \mathrm{HNO}_2} \rightleftharpoons \underset{+5}{\mathrm{HNO}_3}+\underset{+1}{2 \mathrm{NO}}+\mathrm{H}_2 \mathrm{O} \)

\( \mathrm{H}_3 \mathrm{O}^{+}, \mathrm{NO}_3^{-} \text {and } \mathrm{NO} \)