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Using the method of undetermined coefficients solve d^2y/dx^2 + 2dy/dx + 4y = 2x^2 + 3e^-x.

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Using the method of undetermined coefficients solve d2y/dx2 + 2dy/dx + 4y = 2x2 + 3e-x.

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We have (D2 + 2D + 4)y = 2x2 + 3e–x 

A.E. is m2 + 2m + 4 = 0

asked Dec 17, 2023 in Probability Distribution by (25 points) Assignment maths
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