Correct option is (b) λ ≠ 8
For a system of linear equations having unique solution, value of the determinant should not be 0.
Here, \(\Delta = \begin{vmatrix} 1&1&-1\\1&2&-3\\2&5&-\lambda \end{vmatrix}\ne 0\)
\(\Rightarrow [-2\lambda + 15 - 1(-\lambda + 6) - (5-4)] \ne 0\)
\(\Rightarrow -\lambda + 8 \ne 0\)
\(\Rightarrow \lambda \ne 8\)