We know that P = V2/R or R = V2/P.
\(\frac{R_{25}}{R_{100}} = \frac{P_{100}}{P_{25}} = \frac{100}{25} \) = 4
Power dissipated,
\(\frac{P'25}{P'100} = \frac{I^2R_{25}}{I^2R_{100}} = \frac{R_{25}}{R_{100}}\) = 4
Bulb of 25 W will glow brighter and will consume power 4 times more than 100 W bulb.