Question

Calculate the current shown by ammeter A in the circuit diagram given below.

Answer 1

The equivalent circuit is shown in the Fig. The resistance of branch PQ is

R₁ = \(\frac{10\times10}{10+10} + \frac{10\times10}{10+10}\)

or R₁ = 5 + 5 = 10 Ω

Now the resistances AB, PQ and CD are in parallel, so their equivalent resistance is

or R = 2
So current, I = \(\frac{E}{R} = \frac{10}{2} \) = 5 A