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x और y में एक सम्बन्ध स्थापित करें यदि बिन्दु (x, y), (1, 2) तथा (7, 0) सरेखी हैं।

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यदि तीनों बिन्दु संरेखी हैं, तो तीनों बिन्दुओं से बने त्रिभुज का क्षेत्रफल = 0

यहाँ \(\left(x_{1}, y_{1}\right)=(x, y),\left(x_{2}, y_{2}\right)=(1,2)\) तथा \(\left(x_{3}, y_{3}\right)=(7,0)\)

अब तीनों बिन्दुओं से बने त्रिभुज का क्षेत्रफल

\(=1 / 2\left[x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right] \)

\(=1 / 2[x(2-0)+1(0-y)+7(y-2)]\)

\(=1 / 2[2 x-y+7 y-14]\)

\(=1 / 2[2 x+6 y-14]\)

अतः चूँकि तीनों बिन्दु संरेखी हैं, 

\(2 x+6 y-14=0\) अर्थात् \(x+3 y-7=0\).

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