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A compound of carbon, hydrogen and nitrogen contains these elements in the ratio 9:1:3.5. Calculate the empirical formula.

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A compound of carbon, hydrogen and nitrogen contains these elements in the ratio 9:1:3.5. Calculate the empirical formula. If its molecular mass is 108, what is the molecular formula?

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Empirical Formula C3H4N 

Empirical formula mass = (3 × 12) + (4 × 1) + 14 = 54 

Thus, molecular formula of the compound = 2 × empirical formula= 2 × C3H4N = C6H8N2 

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