Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
109 views
in Physics by (53.1k points)
closed by

कोई रैखिक आवेश 2 cm दूरी पर 9 x 104 NC-1 विद्युत क्षेत्र उपन्न करता है। रैखिक आवेश घनत्व ज्ञात कीजिए।

1 Answer

+1 vote
by (48.6k points)
selected by
 
Best answer

अनन्त विस्तार के रेखीय आवेश के कारण उत्पन्न विद्युत क्षेत्र की तीव्रता

E = \(\frac{1}{4\pi \varepsilon_0} \frac{2\lambda}{r}\)

जहाँ λ आवेश का रेखीय घनत्व है और r आवेश से प्रेक्षण बिन्दु की दूरी है

प्रश्नानुसार r = 2 cm = 2 x 10-2 m

λ = ?, E = 9 x 104 NC-1

9 x 104 = 9 x 109\(\frac{2\lambda}{2 \times 10^{-2}}\)

λ = 1.0 x 10-7 Cm-1

या λ = 0.1µ Cm-1

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...