\(4 x^{2}-12 x+9=0;\) यहाँ \(a=4, b=12, c=9\)
\(\mathrm{D}=b^{2}-4 a c=(12)^{2}-4 \times 4 \times 9=144-144=0\)
गुणनखंड समीकरण,
\(x=\frac{-b \pm \sqrt{D}}{2 a}\) या,
\(x=\frac{-(-12) \pm \sqrt{0}}{2 \times 4}=\frac{12}{8}\)
\(\therefore x = \frac {3}{2} \,\&\, x= \frac {3}{2}\)
