Alright, here we go:
The formula for an arithmetic sequence is: a_n=a+(n−1)d.
Here, a is the first term, d is the common difference, and a_n is the nth term.
For the sequence of multiples of 4, we have:
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The first multiple of 4 greater than 10 is 12.
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The multiples of 4 form a sequence: 12, 16, 20, ..., up to the largest multiple of 4 less than 250, which is 248.
In this arithmetic sequence:
Now, to find the number of terms (n) between 12 and 248, we set a_n=248 and solve for n:
248=12+(n−1)⋅4
248−12=(n−1)⋅4
236=(n−1)⋅4
n−1=59
n=60
So, there are 60 multiples of 4 between 10 and 250.