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चित्र में प्रदर्शित नेटवर्क में बिन्दुओं A व B के मध्य विभवान्तर (VB - VD) ज्ञात कीजिए।

नेटवर्क में बिन्दुओं A व B

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प्रश्नानुसार ABC भाग का प्रतिरोध

RABC = 2 + 3 = 5Ω 

और ADC भाग का प्रतिरोध

RADC = 3 + 2 = 5Ω 

∴ RABC  = RADC 

अत: बिन्दु A से धारा दो समान भागों में विभाजित होती है।

i = \(\frac{2}{2}\) = 1A

∴ VA - VB = 2 x 1 = 2 वोल्ट ..............(1)

तथा  VA - VD = 3 x 1 = 3 वोल्ट ..............(2)

समो. (2) में से (1) को घटाने पर

VB - VD = 1 वोल्ट 

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