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\(\int \frac{\sec ^{2}(\log x)}{x}\) का मान ज्ञात करें।

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\(\int \frac{\sec ^{2}(\log x)}{x} d x\)

\(Z=\log x=\int \frac{\sec ^{2} z}{x} d x \cdot x ; \)

\(\frac{d z}{d x}=\frac{1}{x}=\int \sec ^{2} z d x \)

\(\therefore d x=d z \cdot x=\tan z+c=\tan (\log x)+c\)

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