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सिद्ध करें कि वक्र \(y=7 x^{3}+11\) के उन बिंदुओं पर स्पर्श रेखाएँ समांतर हैं जहाँ x = 2 तथा x = -2.

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\(y=7 x^3+11 ; \) 

\(\frac{d y}{d x}=21 x^2\)

at \(x=2, y=67\)

Slope of tangent \(=21.4=84\)

Eqn. of tangent at (2, 67) is \(y-y_1=\) slope \(\left(x-x_1\right)\)

\(\Rightarrow y-67=84(x-2)\) 

\(\Rightarrow y-67=84 x-168\)

\( \Rightarrow 84 x-y=101\) ....(i)

at \(x=-2, y=-56+11=-45\)

Slope of tangent = 84 eqn of tangent is \(y-y_1=\) slope \(\left(x-x_1\right)\)

\(\Rightarrow y-(-45)=84(x+2) \)

\(\Rightarrow y+45=84 x+168 \)

\(\Rightarrow 84 x-y=-123\) ....(ii)

Eqn. (i) and (ii) are parallel. 

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