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A spherical surface of radius of curvature R, separates a rarer and a denser medium as shown in the figure. Complete the path of the incident ray of light, showing the formation of a real image. Hence derive the relation connecting object distance ‘u’, image distance ‘v’, radius of curvature R and the refractive indices n1 and n2 of two media.

Briefly explain how the focal length of a convex lens changes, with increase in wavelength of incident light.

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Sign Conventions

  • All the distances are to be measured from the pole of spherical surface.
  • The distances measured in the same direction as the incident light are taken as positive.
  • Distances measured in the direction opposite to the direction of the incident light are taken as negative.

Asumptions:

  • Object is a point object lying on the principal axis.
  • The aperture of refracting edge is small.
  • The indcident ray from the object strikes the surface at a point very close to point so that angles of incidence and refraction are very small.

Derivation: Consider a point object O be situated on the principal axis of the convex spherical surface. Let P be pole and C be centre of curvature and PC = R be the radius of curvature of the surface. Let µ1 and µ2 be refractive indexes of rarer and denser medium respectively as shown in the figure.

Let incident ray OA refracts at point A and bends towards the normal CAN and real image is formed at I.

From Snell’s law, for small i and r, we have

\(\frac{sin\ i}{\sin r} = \frac{i}{r} = \frac{\mu_2}{\mu_1}\)

or µ1 i = µ2 r .............(1)

Derivation

In ∆ AOC,

i = α + γ

In ∆ AIC,

γ = r + ß

or r = γ - ß

Putting the values of i and r in equation (1), we get

µ1 (α + γ) = µ2 (γ - ß)

or µ1α + µ1γ = µ2γ - µ2ß

or µ1α + µ2ß = (µ2 - µ1) γ ..........(2)

Since α, ß and γ are small, so they can be replaced by their tangents. So equation (2) becomes

equation

Using sign conventions,

PO = -u, PI = v and PC = R,

we get

conventions

When wavelength is increased, the value of n decreases and hence the focal length of the lens increases with increase in wavelength.

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