Question

The energy of an electron in an excited hydrogen atom is -3.4 eV. Calculate the angular momentum of the electron according to Bohr’s theory.

(Given Rydberg’s constant R = 1.09737 x 10^-7 m^-1, h = 6.626176 x 10^-34 Js, c = 3 x 10⁸ ms^-1)

Answer 1

Energy of electron in nth orbit of hydrogen atom

or n² = \(\frac{13.6}{3.4} = 4\)

or n = 2

For Bohr's quatum condition, angular momentum

mvr = \(\frac{nh}{2\pi}\)

or = \(\frac{2 \times 6.626176 \times10^{-34}}{2\times3.142}\)

= 2.1102 x 10^-34 Js.