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in Kinematics by (15 points)
72. A man standing on a road has to hold his um with the vertical to keep the rain away. He throws umbrella and starts running at \( 6 km / hr \) then he finds rain drops are hitting his head vertically, then speed rain drops with respect to moving man: (a) \( 20 km / hr \). (b) \( 8 km / hr \). (c) \( \frac{10}{\sqrt{3}} km / hr \). (d) \( 10 km / hr \).

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Correct option is : (a) 20 km/h

When the man is at rest with respect to the ground, the rain comes to him at an angle 30 with the vertical. This is the direction of the velocity of raindrops with respect to the ground. The situation when the man runs is shown in the figure 

When the man is at rest with respect

\(V_{rg}\)= velocity of rain drops with respect to ground.

\(V_{man}\)= velocity of man =10 km/h

Hence,  \(\cos\ \theta = \frac{10}{V_{rg}}\)

\(\Rightarrow \cos 60^\circ = \frac{10}{v_{rg}}\)

\(\Rightarrow \frac{1}{2} =- \frac{10}{V_{rg}}\)

\(\Rightarrow V_{rg} = 20\ km/h\)

Hence, velocity of rain drops with respect to the ground is 20 km/h.

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