Laws of Radioactive disintegration
- Radioactivity is spontaneous process which does not depend upon external factors.
- During disintegration either α or ß-particle is emitted. Both are never emitted simultaneously.
- Emission of α-particle decreases atomic number by two and mass number by 4.
- Emission of ß-particle increases atomic number by one but mass number remains the same.
- Emission of γ-ray does not change atomic or mass number.
- The number of atoms disintegrated per second is directly proportional to the number of radioactive atoms actually present at that instant. This law is called radioactive decay law.
Let at t = 0
N0 = number of atoms present
N = number of atom left after time t.
dN = number of atoms disintegrated in time dt.
i.e. \(-\frac{dN}{dt} \) ∝ N
or \(-\frac{dN}{dt} \) = λN, ..........(i)
where λ is a constant called disintegration constant and depends upon the nature of the radioactive substance.
Now from, (i), we have
\(\frac{1}{N}\) dN = -λ dt
or ∫ \(\frac{1}{N}\) dN = -λ∫ dt
or logeN = λt + C, .........(ii)
where C is constant of integration. To determine its value,
since N = N0 initially,
i.e. when t = 0, N = N0
logeN0 = 0 + C
Substituting the value of C in (ii), we have
logeN = -λt + logeN0
or logeN - logeN0 = -λt
loge \(\frac{N}{N_0}\) = -λt
or \(\frac{N}{N_0}\) = e-λt
or N = N0 e-λt ............(iii)
which is the required equation.
Eq. (iii) shows that the radioactive decay occurs according to exponential law and the number of radioactive atoms decreases exponentially. Since N shall become zero only when t becomes infinity, it shows that time taken by a radioactive element to disintegrate completely is infinitely long.
The curve in Fig. shows the exponential decay radioactive substance.

Disintegration constant
In Eq. (iii), if t = 1/λ
Then N = N0 e-λx\(\frac{1}{\lambda}\) = = N0e-1 = \(\frac{N_0}{e}\)
Thus disintegration constant is defined as the time after which the number of radioactive atoms reduce to 1/e times the original number of atoms.