Question

Write the electronic configuration of Ce³⁺ ion and calculate the magnetic moment on the basis of spin-only formula. (Atomic number of Ce = 58) 

Answer 1

(i) Write the configuration of Ce and Ce³⁺. 

(ii) Find the number of unpaired electrons. 

(iii) Calculate magnetic momentu, using formula, 

u = \(\sqrt{n(n+2)}\)

58Ce = [Xe]4f¹5d¹6s¹; Ce³⁺ = [Xe] 4f¹5d⁰6s⁰

 u = \(\sqrt{n(n+2)}\)

(n = number of unpaired electrons)

  u = \(\sqrt{n(n+2)}\)

= 1.73 BM