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2. If \( x=\sqrt[3]{9}, y=\sqrt[4]{11}, z=\sqrt[6]{17} \) then : a) \( x>y>z \) b) \( y>z>x \) c) \( z>y>x \)

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Correct option: (A) x > y > z

\(x=9^{1/3}=\sqrt[12]{9y}\)

\(y=\sqrt[4]{11}=\sqrt[12]{11^3}\)

\(z=\sqrt[6]{17}=\sqrt[12]{17^2}\)

As 9>11> 172 

⇒ x > y > z

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