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in Integrals calculus by (15 points)
If \( \int_{\ln 2}^{x}\left(e^{x}-1\right)^{-1} d x=\ln \left(\frac{3}{2}\right) \) then \( x= \)

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\(\int \limits_{\ln 2}^x \frac1{e^x - 1}dx = \ln\frac 32\)

\(\Rightarrow \int\limits_{\ln 2}^x \frac{e^{-x}}{1-e^{-x}} dx = \ln\frac 32\)

\(\Rightarrow \log 1 .{e^{{-x}^x}}_{\ln _2} = \ln \frac 32\)

\(\Rightarrow \log 1 - e^{-x} - \log \frac12 = \ln \frac 32\)

\(\Rightarrow \frac{2e^x-1}{e^x} = \frac 32\)

\(\Rightarrow x = \ln 4\)

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