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A ball of mass m moves on circular paths of radius r1 and r2 with speed v1 and v2 respectively. If r1 < r2 then establish the relation between v1 and v2 while centripetal acceleration in both situations is same.

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Centripetal acceleration, ac = \(\frac {v_2}r\)

\(\because a_1 = a_2 \)

\(\therefore \frac{v_1^2}{r_1} = \frac{v_2^2}{r_2}\)

or \(\frac{v_1^2}{v_2^2} = \frac{r_1}{r_2}\)

or \(\frac{v_1}{v_2} = \sqrt{r_1} r_2 \quad .....(1)\)

∵ Given, r1 < r2

∴ Hence, v< v2

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