Centripetal acceleration, ac = \(\frac {v_2}r\)
\(\because a_1 = a_2 \)
\(\therefore \frac{v_1^2}{r_1} = \frac{v_2^2}{r_2}\)
or \(\frac{v_1^2}{v_2^2} = \frac{r_1}{r_2}\)
or \(\frac{v_1}{v_2} = \sqrt{r_1} r_2 \quad .....(1)\)
∵ Given, r1 < r2
∴ Hence, v1 < v2