Question

The pulleys and strings shown in figure are frictionless. What will be the value 0 for equilibrium of the system?

(a) 0°

(b) 30°

(c) 45°

(d) 60°

Answer 1

Correct option is : (c) 45°

In equilibrium,

2T cos θ = \(\sqrt{2}\ mg\)

\(\therefore\cos\theta = \frac{\sqrt{2}mg}{2T} = \frac{mg}{\sqrt{2}T}\) 

∵ T = mg,

\(\therefore\ \cos \theta = \frac{1}{\sqrt{2}}\Rightarrow\theta = 45^\circ\)

∴ Option (c) is correct.