Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
36 views
in Physics by (58.6k points)
closed by

A rope is tied with a balloon of mass m and a man of mass m is suspending from this balloon by catching the rope in his hands. If the man starts climbing on this rope then the balloon will move with what velocity and in which direction? Velocity of man with respect to rope is v.

1 Answer

+1 vote
by (59.1k points)
selected by
 
Best answer

Initial momentum of man and balloon is zero, therefore on climbing upwards by man, the balloon will move downwards with velocity u such that the combined momentum of balloon and man may remains zero. The velocity of man with respect to Earth will be (v - u), therefore

m(v - u) - Mu = 0 or mv - mu = Mu

or mv = (Mu + mu)

∴ mv = u(M + m)

\(\therefore\ \mu = \frac{mv}{M + m}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...