According to this law, "Rate of change of momentum of a moving body is directly proportional to force applied on the body and in same direction in which force is applied.
Suppose the momentum of a moving body is \(\vec p\), then rate of change of momentum \( = \frac{d\vec p}{dt}\)
∴ According to second law of motion, the force acting on the body,
\(\vec F\propto\frac{d\vec p}{dt}\)
or \(\vec F = K\frac{d\vec p}{dt}\ ...(1)\)
where K is constant of proportionality. The value of K depends on the system of chosen unit. We chose the units Such that
K = 1
\(\therefore\ \vec F = \frac{d\vec p}{dt}\ ...(2)\)
Second law of motion is known as real law.
Therefore the force applied on a body is defined by the product of mass of body and acceleration produced.
Case (ii) When Velocity is constant, then
\(\frac{dv}{dt} = 0\)
\(\therefore\ \vec F =\vec v\frac{dm}{dt}\)
Unit of force : ∵ F = ma
∴ In M.K.S. system, unit of F = kg.ms-2 = Newton (N)
In C.G.S. system, unit of F= g.cm.s-2 = dyne
Dimensions: ∵ F = ma
∴ Dimensional formula of F = [M1L1T-2]
Relation between N and dyne:
\(1\ N = 1 \ Kg\times\frac{1m}{1s^2} = \frac{1000g\times100cm}{s^2}\)
= 105 g.cm.s-2
or 1 N = 105 dyne
Definition of N: ∵ F= ma
If m = 1 kg; a = 1 ms-2; then F = 1 N
Thus, “1 N is the force which can produce an acceleration of 1 ms-2 in an object of mass 1 kg.”