Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
35 views
in Chemistry by (60.5k points)
edited by

प्रकाश रासायनिक तुल्यांक के नियमानुसार अवशोशित ऊर्जा (erg/ mol में) को दर्शाया जाएगा। (h = 6.62 x 10-27 erg, c = 3 x 101 cm s-1, N, = 6.02 x 1023 mol-1)

(a) \(\frac{1.196 \times 10^8}{\lambda}\) 

(b) \(\frac{2.859 \times 10^5}{\lambda}\)

(c) \(\frac{2.859 \times 10^{16}}{\lambda}\) 

(d) \(\frac{1.196 \times 10^{16}}{\lambda}\)

Please log in or register to answer this question.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...