Question

A car of mass m is moving on circular plane path. If coefficient of friction between road and tyres is µs, then what will be maximum rotational speed of the care?

\((a)\ \sqrt{\mu_s.mRg}\)

\((b)\ \sqrt{Rg/\mu_s}\)

\((c) \sqrt{\frac{mRg}{\mu_s}}\) 

\((d) \ \sqrt{\mu_sRg}\)

Answer 1

Correct option is :  \((d) \ \sqrt{\mu_sRg}\)

For safe turn on the circular path, centripetal force = friction force

or \(\frac{mv^2}{R} = \mu mg\)

\(\therefore\ v^2 = \mu Rg\)

or \(v = \sqrt{\mu Rg}\)

∴ Option (d) is correct.