(i) [Fe(EDTA)]-
x + (-4) x 1
x = 3 - 1
∴ x = +3 Fe की आँ. सं. = + 3
(ii) [Pd(H2O)2(ONO)2I2]
x + 2 x 0 + 2 x (-1) + 2 x (-1) = 0
x + (-2) + (-2) =0
x - 4 = 0
∴ x = +4 Pd की ऑ. सं. = + 4
(iii) [CO(NH3)5Cl]2+
x + 5 x 0 + (-1) = +2
∴ x = +3
CO की ऑ. सं. = +3
(iv) K4[Fe(CN)6]
4 x (+1) + x + 6 x (-1)= 0
+4 + x - 6 = 0
∴ x = +2 Fe की ऑ. संख्या = + 2