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निम्नलिखित संकुलों की ऑक्सीकरण संख्या ज्ञात कीजिए। 

(i) [Fe(EDTA)]- 

(ii) [Pd(H2O)2(ONO)2I2]

(iii) [CO(NH3)5Cl]2+ 

(iv) K4[Fe(CN)6]

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(i) [Fe(EDTA)]- 

 x + (-4) x 1

 x = 3 - 1

 ∴ x = +3 Fe की आँ. सं. = + 3 

(ii) [Pd(H2O)2(ONO)2I2]

x + 2 x 0 + 2 x (-1) + 2 x (-1) = 0 

x + (-2) + (-2) =0

x - 4 = 0 

∴ x = +4 Pd की ऑ. सं. = + 4 

(iii) [CO(NH3)5Cl]2+

x + 5 x 0 + (-1) = +2

∴ x = +3

CO की ऑ. सं. = +3 

(iv) K4[Fe(CN)6]

4 x (+1) + x + 6 x (-1)= 0

+4 + x - 6 = 0 

∴ x = +2 Fe की ऑ. संख्या = + 2 

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