Question

In the reaction I₂ + 2S₂O₃^- → 2I^- + S₄O₆^2- 

equivalent weight of iodine will be equal to

(a) molecular weight

(b) 1/2 the molecular weight

(c) 1/4 the molecular weight

(d) twice the molecular weight

Answer 1

Correct option is (b) 1/2 the molecular weight

Eq. mass of I₂ = \(\frac{\text{mol. mass}}{\text{change in ox. no. of 2I atoms}}\)

\(= \frac{\text{mol. mass}}{0 - 2(-1)}\)

\(= \frac{\text{mol. mass}}{2}\)