Question

Volume of 0.6 M NaOH required to neutralize 30 cm³ of 0.4 M HCl is

(a) 30 cm³

(b) 20 cm³

(c) 50 cm³

(d) 45 cm³

Answer 1

Correct option is (b) 20 cm³

Given,

For NaOH,

V₁ = ?

M₁ = 0.6 M

For HCI, V₂ = 300 cm³, M₂ = 0.4 M.

Now, M₁V₁ = M₂V₂

\(\Rightarrow V_1 = \frac{M_2V_2}{M_1}\)

\(= \frac{0.4 \times 30}{0.6}\)

V₁ = 20 cm³