Question

Number of moles of KMnO₄ required to oxidise one mole of Fe(C₂O₄) in acidic medium is

(a) 0.2

(b) 0.4

(c) 0.6

(d) 1.67

Answer 1

Correct option is (c) 0.6

MnO₄^- + Fe²⁺ + C₂O₄^2- + 8H⁺ → Mn²⁺ + Fe³⁺ + 2CO₂ + 4H₂O

Electrons gained by 1 mole of MnO₄^- = 7 - 2 = 5 moles

Electrons given by FeC₂O₄ = (3 - 2) + 2(4 - 3) = 3

Hence, no. of moles of KMnO₄ required to oxidise 1 mole of FeC₂O₄ = \(\frac 35\) = 0.6