Question

Given the statement and proof of theorem of parallel axes of moment of inertia.

Answer 1

Moment of inertia of the disc about the tangential axis in the plane of the disc: We have to find the moment of inertia of the disc about the tangential axis PQ parallel to the diameter AB. From the theorem of parallel axes,

I_PQ = I_cm + Mh²

^{\(= I_{AB} + MR^2 = \frac{1}{2}MR^2 + MR^2\)}

or \(I_{PQ} = \frac{5}{4}MR^2\)