Question

In molecule of carbon mono-oxide the distance between carbon and oxygen atoms is 1.150 Å. Give the situation of centre of mass of CO molecule with respect to carbon atom.

Answer 1

m₁r₁ = m₂r₂

\(\therefore\ 12\times x = 16(1.15-x)\)

3x = 4(1.15 - x)

or 3x = 4.60 - 4x

7x = 4.60

∴ x = \(\frac{460}{7}\) = 0.6571 Å

or x = 0.6571 Å

Based on Torque, Angular Momentum and Laws of Rotational Motion